feat: add maxConsecutiveOnesIII implementation

Dynamic-Programming/Sliding-Window/MaxConsecutiveOnesIII.js

@@ -0,0 +1,32 @@
+/**
+ * @function maxConsecutiveOnesIII
+ * @description Given a binary array nums and an integer k, return the maximum number of consecutive 1's in the array if you can flip at most k 0's.
+ * @param {number[]} nums
+ * @param {number} k
+ * @return {number}
+ * @see [Leetcode link](https://leetcode.com/problems/max-consecutive-ones-iii/)
+ */
+export const maxConsecutiveOnesIII = (nums, k) => {
+  if (!nums.length) return 0
+
+  let result = 0
+
+  for (
+    let slowPointer = 0, fastPointer = 0;
+    fastPointer < nums.length;
+    fastPointer++
+  ) {
+    if (nums[fastPointer] === 0) {
+      k--
+    }
+
+    while (k < 0) {
+      if (slowPointer === 0) {
+        k++
+      }
+      slowPointer++
+    }
+    result = Math.max(result, fastPointer - slowPointer + 1)
+  }
+  return result
+}

Dynamic-Programming/Sliding-Window/test/MaxConsecutiveOnesIII.test.js

@@ -0,0 +1,15 @@
+import { maxConsecutiveOnesIII } from '../MaxConsecutiveOnesIII'
+
+describe('maxConsecutiveOnesIIIIII', () => {
+  it('expects to return 0 when argument is empty array', () => {
+    expect(maxConsecutiveOnesIII([], 3)).toBe(0)
+  })
+
+  it('expects to return 6', () => {
+    expect(maxConsecutiveOnesIII([1, 1, 0, 1, 1, 1], 1)).toBe(6)
+  })
+
+  it('expects to return 8', () => {
+    expect(maxConsecutiveOnesIII([1, 0, 1, 1, 1, 1, 0, 1], 2)).toBe(8)
+  })
+})