refactor: Remove comments from Solution1.py and add Solution2.py

- Removed all comments from Solution1.py to avoid over-reliance on comments while practicing.
- Implemented a solution for the factorial calculation problem in Solution2.py.
- Ensured proper function naming, parameter handling, and edge case coverage.
- Fixed syntax issues and improved the function’s clarity.

Author: YutingLi2001

Solutions by Yuting/Solution1.py

@@ -1,33 +1,8 @@
 from typing import List
-
-def find_numbers(numbers: List[int], divisible_by: int, not_multiple_of: int) -> str:
-    """
-    Finds all numbers in the given list that are divisible by `divisible_by`
-    but not a multiple of `not_multiple_of`. Returns them as a comma-separated string.
-
-    Args:
-        numbers (List[int]): The list of numbers to check.
-        divisible_by (int): The divisor to filter numbers that are divisible.
-        not_multiple_of (int): The number that filtered numbers should not be a multiple of.
-
-    Returns:
-        str: A comma-separated string of valid numbers.
-    """
-    if not numbers:
-        return ""  # Return empty string for an empty list
-
-    # List comprehension for efficient filtering
-    valid_numbers = [str(num) for num in numbers if num % divisible_by == 0 and num % not_multiple_of != 0]
-
-    return ",".join(valid_numbers)  # Join the numbers as a single string
-
-
+def find_numbers(nums: List[int], divisible_by: int, not_multiple_of: int) -> str:
+    if len(nums) == 0: return ""
+    return ",".join((str(num) for num in nums if num % divisible_by == 0 and num % not_multiple_of != 0))
 if __name__ == "__main__":
-    # Define the range of numbers to check
-    numbers_range = list(range(2000, 3201))
-
-    # Set conditions: Divisible by 7 but not a multiple of 5
-    result = find_numbers(numbers_range, divisible_by=7, not_multiple_of=5)
-
-    # Print the result to standard output
-    print(result)
+    sample_entry = list(range(2000,3201))
+    sample_result = find_numbers(nums = sample_entry, divisible_by=7, not_multiple_of=5)
+    print(sample_result)

Solutions by Yuting/Solution2.py

@@ -0,0 +1,21 @@
+'''
+Question:
+Write a program which can compute the factorial of a given numbers.
+The results should be printed in a comma-separated sequence on a single line.
+Suppose the following input is supplied to the program:
+8
+Then, the output should be:
+40320
+'''
+def factorial_calculator(n: int) -> str:
+    # By mathematical definition, 0! (zero factorial) is equal to 1.
+    # This is a standard convention used in combinatorics and algebra.
+    ans = 1
+    for i in range(1, n + 1):
+        ans *= i
+    return str(ans)
+
+if __name__ == '__main__':
+    sample_input = 8
+    sample_result = factorial_calculator(sample_input)
+    print(sample_result)