Create Maximum Area of Longest Diagonal Rectangle.py

Signed-off-by: Erjan <erjan@users.noreply.github.com>

Author: erjan

Maximum Area of Longest Diagonal Rectangle.py

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+You are given a 2D 0-indexed integer array dimensions.
+
+For all indices i, 0 <= i < dimensions.length, dimensions[i][0] represents the length and dimensions[i][1] represents the width of the rectangle i.
+
+Return the area of the rectangle having the longest diagonal. If there are multiple rectangles with the longest diagonal, return the area of the rectangle having the maximum area.
+
+  ------------------------------------------------------------------------------------------------
+
+class Solution:
+    def areaOfMaxDiagonal(self, dimensions: List[List[int]]) -> int:
+        maxdiag = 0
+        maxres = 0
+
+        print(dimensions)
+        for i in range(len(dimensions)):
+            w,h = dimensions[i]
+
+
+            diag = (w*w + h*h)**0.5
+            cur_res = w*h
+
+            dimensions[i].extend([diag,cur_res])
+        
+
+        dimensions.sort(key = lambda x: (x[2], x[3]))
+
+        res = dimensions[-1][3]
+
+        return res
+
+--------------------------------------------------
+
+#other solution
+
+class Solution:
+    def areaOfMaxDiagonal(self, dimensions: list[list[int]]) -> int:
+        max_area, max_diag = 0, 0
+
+        for l, w in dimensions:
+            curr_diag = l * l + w * w
+            if curr_diag > max_diag or (curr_diag == max_diag and l * w > max_area):
+                max_diag = curr_diag
+                max_area = l * w
+
+        return max_area