some array practice

Author: linyanna

data_structures/2_Arrays/2_expenses_attempt.py

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+
+# Question 1
+expenses = [2200, 2350, 2600, 2130, 2190]
+
+#1
+answer1 = expenses[1]-expenses[0]
+
+#2
+total = 0
+for i in range(3):
+  total += expenses[i]
+answer2 = total
+
+#3
+spent2000 = False
+for i in expenses:
+  if i==2000:
+    spend2000 = True
+answer3 = spent2000
+
+#4
+expenses.append(1980)
+answer4 = expenses
+
+#5
+expenses[3] -= 200
+answer5 = expenses
+
+# Print Answers
+print("answer 1: ", answer1, "\nanswer2: ", answer2, "\nanswer3: ", answer3, "\nanswer4: ",  answer4,  "\nanswer5: ",  answer5)

data_structures/2_Arrays/2_only_odd.py

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+max = int(input("Enter max number: "))
+
+def onlyOdd(max):
+  oddList = []
+  for i in range(1, max):
+    if (i % 2) == 1:
+      oddList.append(i)
+
+  return oddList
+
+
+def main():
+  print("Odd numbers: ", onlyOdd(max))
+
+main()