refactor 1396

Author: fishercoder1534

src/main/java/com/fishercoder/solutions/_1396.java

@@ -4,51 +4,6 @@
 import java.util.LinkedList;
 import java.util.Map;
 
-/**
- * 1396. Design Underground System
- *
- * Implement the class UndergroundSystem that supports three methods:
- *
- * 1. checkIn(int id, string stationName, int t)
- * A customer with id card equal to id, gets in the station stationName at time t.
- * A customer can only be checked into one place at a time.
- * 2. checkOut(int id, string stationName, int t)
- * A customer with id card equal to id, gets out from the station stationName at time t.
- * 3. getAverageTime(string startStation, string endStation)
- * Returns the average time to travel between the startStation and the endStation.
- * The average time is computed from all the previous traveling from startStation to endStation that happened directly.
- * Call to getAverageTime is always valid.
- * You can assume all calls to checkIn and checkOut methods are consistent. That is, if a customer gets in at time t1 at some station, then it gets out at time t2 with t2 > t1. All events happen in chronological order.
- *
- * Example 1:
- * Input
- * ["UndergroundSystem","checkIn","checkIn","checkIn","checkOut","checkOut","checkOut","getAverageTime","getAverageTime","checkIn","getAverageTime","checkOut","getAverageTime"]
- * [[],[45,"Leyton",3],[32,"Paradise",8],[27,"Leyton",10],[45,"Waterloo",15],[27,"Waterloo",20],[32,"Cambridge",22],["Paradise","Cambridge"],["Leyton","Waterloo"],[10,"Leyton",24],["Leyton","Waterloo"],[10,"Waterloo",38],["Leyton","Waterloo"]]
- * Output
- * [null,null,null,null,null,null,null,14.0,11.0,null,11.0,null,12.0]
- *
- * Explanation
- * UndergroundSystem undergroundSystem = new UndergroundSystem();
- * undergroundSystem.checkIn(45, "Leyton", 3);
- * undergroundSystem.checkIn(32, "Paradise", 8);
- * undergroundSystem.checkIn(27, "Leyton", 10);
- * undergroundSystem.checkOut(45, "Waterloo", 15);
- * undergroundSystem.checkOut(27, "Waterloo", 20);
- * undergroundSystem.checkOut(32, "Cambridge", 22);
- * undergroundSystem.getAverageTime("Paradise", "Cambridge");       // return 14.0. There was only one travel from "Paradise" (at time 8) to "Cambridge" (at time 22)
- * undergroundSystem.getAverageTime("Leyton", "Waterloo");          // return 11.0. There were two travels from "Leyton" to "Waterloo", a customer with id=45 from time=3 to time=15 and a customer with id=27 from time=10 to time=20. So the average time is ( (15-3) + (20-10) ) / 2 = 11.0
- * undergroundSystem.checkIn(10, "Leyton", 24);
- * undergroundSystem.getAverageTime("Leyton", "Waterloo");          // return 11.0
- * undergroundSystem.checkOut(10, "Waterloo", 38);
- * undergroundSystem.getAverageTime("Leyton", "Waterloo");          // return 12.0
- *
- * Constraints:
- * There will be at most 20000 operations.
- * 1 <= id, t <= 10^6
- * All strings consist of uppercase, lowercase English letters and digits.
- * 1 <= stationName.length <= 10
- * Answers within 10^-5 of the actual value will be accepted as correct.
- * */
 public class _1396 {
     public static class Solution1 {
         public class UndergroundSystem {