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|  | 1 | +package com.leetcode.graphs; | 
|  | 2 | + | 
|  | 3 | + | 
|  | 4 | +import javafx.util.Pair; | 
|  | 5 | + | 
|  | 6 | +import java.util.*; | 
|  | 7 | + | 
|  | 8 | +import static org.junit.jupiter.api.Assertions.assertEquals; | 
|  | 9 | + | 
|  | 10 | +/** | 
|  | 11 | + * Level: Medium | 
|  | 12 | + * Link: https://leetcode.com/problems/word-ladder/ | 
|  | 13 | + * Description: | 
|  | 14 | + * Given two words (beginWord and endWord), and a dictionary's word list, find the length of shortest transformation | 
|  | 15 | + * sequence from beginWord to endWord, such that: | 
|  | 16 | + * <p> | 
|  | 17 | + * Only one letter can be changed at a time. Each transformed word must exist in the word list. Note that beginWord | 
|  | 18 | + * is not a transformed word. | 
|  | 19 | + * <p> | 
|  | 20 | + * Note: | 
|  | 21 | + * - Return 0 if there is no such transformation sequence. | 
|  | 22 | + * - All words have the same length. | 
|  | 23 | + * - All words contain only lowercase alphabetic characters. | 
|  | 24 | + * - You may assume no duplicates in the word list. | 
|  | 25 | + * - You may assume beginWord and endWord are non-empty and are not the same. | 
|  | 26 | + * <p> | 
|  | 27 | + * Example 1: | 
|  | 28 | + * Input: | 
|  | 29 | + * beginWord = "hit", | 
|  | 30 | + * endWord = "cog", | 
|  | 31 | + * wordList = ["hot","dot","dog","lot","log","cog"] | 
|  | 32 | + * <p> | 
|  | 33 | + * Output: 5 | 
|  | 34 | + * <p> | 
|  | 35 | + * Explanation: As one shortest transformation is "hit" -> "hot" -> "dot" -> "dog" -> "cog", | 
|  | 36 | + * return its length 5. | 
|  | 37 | + * <p> | 
|  | 38 | + * Example 2: | 
|  | 39 | + * Input: | 
|  | 40 | + * beginWord = "hit" | 
|  | 41 | + * endWord = "cog" | 
|  | 42 | + * wordList = ["hot","dot","dog","lot","log"] | 
|  | 43 | + * <p> | 
|  | 44 | + * Output: 0 | 
|  | 45 | + * <p> | 
|  | 46 | + * Explanation: The endWord "cog" is not in wordList, therefore no possible transformation. | 
|  | 47 | + * | 
|  | 48 | + * @author rampatra | 
|  | 49 | + * @since 2019-08-15 | 
|  | 50 | + */ | 
|  | 51 | +public class WordLadder { | 
|  | 52 | + | 
|  | 53 | +    /** | 
|  | 54 | +     * Runtime: <a href="https://leetcode.com/submissions/detail/251953011/">78 ms</a>. | 
|  | 55 | +     * | 
|  | 56 | +     * @param beginWord | 
|  | 57 | +     * @param endWord | 
|  | 58 | +     * @param wordList | 
|  | 59 | +     * @return | 
|  | 60 | +     */ | 
|  | 61 | +    public static int ladderLength(String beginWord, String endWord, List<String> wordList) { | 
|  | 62 | +        int L = beginWord.length(); | 
|  | 63 | +        Map<String, Set<String>> originalToTransformedWordMap = new HashMap<>(); | 
|  | 64 | +        Queue<Pair<String, Integer>> queue = new LinkedList<>(); | 
|  | 65 | + | 
|  | 66 | +        wordList.forEach(word -> { | 
|  | 67 | +                    String transformedWord; | 
|  | 68 | +                    for (int i = 0; i < L; i++) { | 
|  | 69 | +                        transformedWord = word.substring(0, i) + "*" + word.substring(i + 1, L); | 
|  | 70 | +                        originalToTransformedWordMap.putIfAbsent(transformedWord, new HashSet<>()); | 
|  | 71 | +                        originalToTransformedWordMap.get(transformedWord).add(word); | 
|  | 72 | +                    } | 
|  | 73 | +                } | 
|  | 74 | +        ); | 
|  | 75 | + | 
|  | 76 | +        Set<String> visited = new HashSet<>(); | 
|  | 77 | +        queue.add(new Pair<>(beginWord, 1)); | 
|  | 78 | +        visited.add(beginWord); | 
|  | 79 | + | 
|  | 80 | +        while (!queue.isEmpty()) { | 
|  | 81 | +            Pair<String, Integer> currPair = queue.poll(); | 
|  | 82 | +            String word = currPair.getKey(); | 
|  | 83 | +            Integer level = currPair.getValue(); | 
|  | 84 | + | 
|  | 85 | +            if (word.equals(endWord)) { | 
|  | 86 | +                return level; | 
|  | 87 | +            } | 
|  | 88 | + | 
|  | 89 | +            String transformedWord; | 
|  | 90 | +            for (int i = 0; i < L; i++) { | 
|  | 91 | +                transformedWord = word.substring(0, i) + "*" + word.substring(i + 1, L); | 
|  | 92 | + | 
|  | 93 | +                for (String originalWord : originalToTransformedWordMap.getOrDefault(transformedWord, Collections.emptySet())) { | 
|  | 94 | +                    if (!visited.contains(originalWord)) { | 
|  | 95 | +                        queue.add(new Pair<>(originalWord, level + 1)); | 
|  | 96 | +                        visited.add(originalWord); | 
|  | 97 | +                    } | 
|  | 98 | +                } | 
|  | 99 | +            } | 
|  | 100 | +        } | 
|  | 101 | + | 
|  | 102 | +        return 0; | 
|  | 103 | +    } | 
|  | 104 | + | 
|  | 105 | +    public static void main(String[] args) { | 
|  | 106 | +        assertEquals(5, ladderLength("hit", "cog", Arrays.asList("hot", "dot", "dog", "lot", "log", "cog"))); | 
|  | 107 | +        assertEquals(0, ladderLength("hit", "cog", Arrays.asList("hot", "dot", "dog", "lot", "log"))); | 
|  | 108 | +    } | 
|  | 109 | +} | 
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