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|  | 1 | +package com.leetcode.trees; | 
|  | 2 | + | 
|  | 3 | +import java.util.*; | 
|  | 4 | + | 
|  | 5 | +import static org.junit.jupiter.api.Assertions.assertEquals; | 
|  | 6 | + | 
|  | 7 | +/** | 
|  | 8 | + * Level: Medium | 
|  | 9 | + * Link: https://leetcode.com/problems/binary-tree-zigzag-level-order-traversal/ | 
|  | 10 | + * Description: | 
|  | 11 | + * Given a binary tree, return the zigzag level order traversal of its nodes' values. (ie, from left to right, then | 
|  | 12 | + * right to left for the next level and alternate between). | 
|  | 13 | + * | 
|  | 14 | + * For example: | 
|  | 15 | + * Given binary tree [3,9,20,null,null,15,7], | 
|  | 16 | + *     3 | 
|  | 17 | + *    / \ | 
|  | 18 | + *   9  20 | 
|  | 19 | + *     /  \ | 
|  | 20 | + *    15   7 | 
|  | 21 | + * return its zigzag level order traversal as: | 
|  | 22 | + * [ | 
|  | 23 | + *   [3], | 
|  | 24 | + *   [20,9], | 
|  | 25 | + *   [15,7] | 
|  | 26 | + * ] | 
|  | 27 | + * | 
|  | 28 | + * @author rampatra | 
|  | 29 | + * @since 2019-08-11 | 
|  | 30 | + */ | 
|  | 31 | +public class BinaryTreeZigZagLevelOrderTraversal { | 
|  | 32 | + | 
|  | 33 | +    /** | 
|  | 34 | +     * Time Complexity: | 
|  | 35 | +     * Space Complexity: | 
|  | 36 | +     * Runtime: <a href="https://leetcode.com/submissions/detail/250830618/">1 ms</a>. | 
|  | 37 | +     * | 
|  | 38 | +     * @param root | 
|  | 39 | +     * @return | 
|  | 40 | +     */ | 
|  | 41 | +    public static List<List<Integer>> zigzagLevelOrder(TreeNode root) { | 
|  | 42 | + | 
|  | 43 | +        int levelNo = 0; | 
|  | 44 | +        LinkedList<Integer> currLevel = new LinkedList<>(); | 
|  | 45 | +        List<List<Integer>> levelOrderTraversal = new LinkedList<>(); | 
|  | 46 | + | 
|  | 47 | +        if (root == null) { | 
|  | 48 | +            return levelOrderTraversal; | 
|  | 49 | +        } | 
|  | 50 | + | 
|  | 51 | +        Queue<TreeNode> queue = new LinkedList<>(); | 
|  | 52 | +        queue.add(root); | 
|  | 53 | +        queue.add(null); | 
|  | 54 | + | 
|  | 55 | +        while (!queue.isEmpty()) { | 
|  | 56 | + | 
|  | 57 | +            TreeNode treeNode = queue.poll(); | 
|  | 58 | + | 
|  | 59 | +            if (treeNode == null) { | 
|  | 60 | +                levelOrderTraversal.add(currLevel); | 
|  | 61 | +                currLevel = new LinkedList<>(); | 
|  | 62 | +                levelNo++; | 
|  | 63 | + | 
|  | 64 | +                if (queue.size() > 0) { | 
|  | 65 | +                    queue.add(null); | 
|  | 66 | +                } | 
|  | 67 | +            } else { | 
|  | 68 | +                if (levelNo % 2 == 0) { | 
|  | 69 | +                    currLevel.add(treeNode.val); | 
|  | 70 | +                } else { | 
|  | 71 | +                    currLevel.add(0, treeNode.val); | 
|  | 72 | +                } | 
|  | 73 | +                if (treeNode.left != null) queue.add(treeNode.left); | 
|  | 74 | +                if (treeNode.right != null) queue.add(treeNode.right); | 
|  | 75 | +            } | 
|  | 76 | +        } | 
|  | 77 | + | 
|  | 78 | +        return levelOrderTraversal; | 
|  | 79 | +    } | 
|  | 80 | + | 
|  | 81 | +    public static void main(String[] args) { | 
|  | 82 | +        /* | 
|  | 83 | +            Binary Tree | 
|  | 84 | +
 | 
|  | 85 | +                1 | 
|  | 86 | +               / \ | 
|  | 87 | +              2   3 | 
|  | 88 | +             / \ | 
|  | 89 | +            4   5 | 
|  | 90 | +         */ | 
|  | 91 | +        TreeNode tree = new TreeNode(1); | 
|  | 92 | +        tree.left = new TreeNode(2); | 
|  | 93 | +        tree.right = new TreeNode(3); | 
|  | 94 | +        tree.left.left = new TreeNode(4); | 
|  | 95 | +        tree.left.right = new TreeNode(5); | 
|  | 96 | + | 
|  | 97 | +        assertEquals("[[1], [3, 2], [4, 5]]", zigzagLevelOrder(tree).toString()); | 
|  | 98 | +        assertEquals("[]", zigzagLevelOrder(null).toString()); | 
|  | 99 | +    } | 
|  | 100 | +} | 
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